$\frac{3}{10}$

$\frac{1}{5}$

$\frac{1}{10}$

$\frac{2}{5}$

$0.001$

$0.001$ if she has only one ticket.

$0.5$

At b only your friend's number is right, at c is every even number is right.

$\frac{1}{999}$

$\frac{500}{999}$

$\frac{6}{36}=\frac{1}{6}$

$\frac{21}{36}=\frac{7}{12}$

$\frac{1}{36}$

$\frac{1}{2}$

$\frac{1}{2}$

$\frac{1}{16}$

$\frac{4}{16}$